3a+2[2+3(a-1)]=2(4a-1)+a

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Solution for 3a+2[2+3(a-1)]=2(4a-1)+a equation: 


Simplifying
3a + 2[2 + 3(a + -1)] = 2(4a + -1) + a

Reorder the terms:
3a + 2[2 + 3(-1 + a)] = 2(4a + -1) + a
3a + 2[2 + (-1 * 3 + a * 3)] = 2(4a + -1) + a
3a + 2[2 + (-3 + 3a)] = 2(4a + -1) + a

Combine like terms: 2 + -3 = -1
3a + 2[-1 + 3a] = 2(4a + -1) + a
3a + [-1 * 2 + 3a * 2] = 2(4a + -1) + a
3a + [-2 + 6a] = 2(4a + -1) + a

Reorder the terms:
-2 + 3a + 6a = 2(4a + -1) + a

Combine like terms: 3a + 6a = 9a
-2 + 9a = 2(4a + -1) + a

Reorder the terms:
-2 + 9a = 2(-1 + 4a) + a
-2 + 9a = (-1 * 2 + 4a * 2) + a
-2 + 9a = (-2 + 8a) + a

Combine like terms: 8a + a = 9a
-2 + 9a = -2 + 9a

Add '2' to each side of the equation.
-2 + 2 + 9a = -2 + 2 + 9a

Combine like terms: -2 + 2 = 0
0 + 9a = -2 + 2 + 9a
9a = -2 + 2 + 9a

Combine like terms: -2 + 2 = 0
9a = 0 + 9a
9a = 9a

Add '-9a' to each side of the equation.
9a + -9a = 9a + -9a

Combine like terms: 9a + -9a = 0
0 = 9a + -9a

Combine like terms: 9a + -9a = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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